(x^2-2x+4)+(2x+1)-(x^2+5)=

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Solution for (x^2-2x+4)+(2x+1)-(x^2+5)= equation:


Simplifying
(x2 + -2x + 4) + (2x + 1) + -1(x2 + 5) = 0

Reorder the terms:
(4 + -2x + x2) + (2x + 1) + -1(x2 + 5) = 0

Remove parenthesis around (4 + -2x + x2)
4 + -2x + x2 + (2x + 1) + -1(x2 + 5) = 0

Reorder the terms:
4 + -2x + x2 + (1 + 2x) + -1(x2 + 5) = 0

Remove parenthesis around (1 + 2x)
4 + -2x + x2 + 1 + 2x + -1(x2 + 5) = 0

Reorder the terms:
4 + -2x + x2 + 1 + 2x + -1(5 + x2) = 0
4 + -2x + x2 + 1 + 2x + (5 * -1 + x2 * -1) = 0
4 + -2x + x2 + 1 + 2x + (-5 + -1x2) = 0

Reorder the terms:
4 + 1 + -5 + -2x + 2x + x2 + -1x2 = 0

Combine like terms: 4 + 1 = 5
5 + -5 + -2x + 2x + x2 + -1x2 = 0

Combine like terms: 5 + -5 = 0
0 + -2x + 2x + x2 + -1x2 = 0
-2x + 2x + x2 + -1x2 = 0

Combine like terms: -2x + 2x = 0
0 + x2 + -1x2 = 0
x2 + -1x2 = 0

Combine like terms: x2 + -1x2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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